$\left(y+4\right)^2$
$\tan^2\left(x\right)\csc^2\left(x\right)-\tan^2\left(x\right)$
$16-\left(-60\right)$
$\frac{4}{x+1}=\frac{12}{x+5}$
$\int_0^{\frac{\pi}{6}}\left(secx+tanx\right)^2dx$
$8t^3\:+\:125$
$-7x^2-34x+48$
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