$2x-3=15$
$\int17\sec^4\theta\:\tan^2\theta\:d\theta\:$
$y^2-12=4x-28$
$5d-\left(2-d\right)\cdot5+\left(-3\right)\cdot\left(2d-4\right)$
$2x^3\left(3m+4n\right)+5z^3\left(3m+4n\right)$
$-26+-6+12'$
$10^mx10^n$
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