(20.7)2\left(20.7\right)^2(20.7)2
dydx−4x=sin(5x)\frac{dy}{dx}-4x=\sin\left(5x\right)dxdy−4x=sin(5x)
(−3)2⋅(−2)\left(-3\right)^2\cdot\left(-2\right)(−3)2⋅(−2)
limx→1(3(cos(2x−2))−3x23ln(3−2x))\lim_{x\to1}\left(\frac{3\left(cos\left(2x-2\right)\right)-3x^2}{3ln\left(3-2x\right)}\right)x→1lim(3ln(3−2x)3(cos(2x−2))−3x2)
∫(t5et)dt\int\left(t^5e^t\right)dt∫(t5et)dt
f−19=2f-19=2f−19=2
4x2y3+5y−3x; x=1; y=−14x^2y^3+5y-3x;\:x=1;\:y=-14x2y3+5y−3x;x=1;y=−1
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