$\frac{dy}{dx}+\left(\tan\left(x\right)\right)=\cos\left(x\right)$
$2x^2-2xy+2y^2$
$y^3\left(x^2-4\right)\frac{dy}{dx}=1$
$30xy+28xy+1$
$8^1\cdot8^0$
$4\sqrt{-\frac{1}{8}}$
$\frac{6x^4+5x^3-1}{2x^2+x-1}$
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