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Exercise

$16a^2-24ab+9bx-3\left(6x+5\right)=4x+9\left(2x+11\right)$

Step-by-step Solution

Learn how to solve integrals of rational functions problems step by step online. Solve the equation 16a^2-24ab9bx-3(6x+5)=4x+9(2x+11). Multiply the single term -3 by each term of the polynomial \left(6x+5\right). Multiply the single term 9 by each term of the polynomial \left(2x+11\right). Combining like terms 4x and 18x. Group the terms of the equation.
Solve the equation 16a^2-24ab9bx-3(6x+5)=4x+9(2x+11)

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Final answer to the exercise

$x=\frac{114-16a^2+24ab}{9b-40}$

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Main Topic: Integrals of Rational Functions

Integrals of rational functions of the form R(x) = P(x)/Q(x).

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