$\lim_{x\to0}\left(\frac{8-\sqrt[3]{64+x}}{\sqrt[3]{64+x}-4}\right)$
$\frac{x^2+6x+3}{x+1}$
$\left(\sec x+\csc x\right)\left(\cos x-\sin x\right)$
$\left(4m+3n\right)\left(2m-5n\right)$
$\sqrt{x+1^2}$
$-c^{3\:}.\:c^8$
$x^2y^2-6x^3y^2+9x^4y^2$
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