(1⋅8−40964⋅16+27−63)\left(1\cdot8-\frac{4096}{4\cdot16}+27-63\right)(1⋅8−4⋅164096+27−63)
3x2−7x6+3<8\:\frac{3x}{2}-\frac{7x}{6}+3<823x−67x+3<8
2x2−11x2x^2-11x2x2−11x
∫(x2csc2(x3+2))dx\int\left(x^2csc^2\left(x^3+2\right)\right)dx∫(x2csc2(x3+2))dx
∫ (2x−3)3e9dx\int\:\left(2x-3\right)^3e^9dx∫(2x−3)3e9dx
∫x2−7xdx\int\frac{\sqrt{x^2-7}}{x}dx∫xx2−7dx
x⋅x16x\cdot x^{\frac{1}{6}}x⋅x61
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