$\left(4x-9y\right)^2$

$\frac{d^3}{dx^3}\left(\cos\left(x\right)\cdot\ln\left(1+x\right)\right)$

$3\left(3d\:-\:4e\right)\:+\:2\left(d\:-\:5e\right)$

$[\left(x+2\right)\left(x+4\right)-4]$

$\frac{x+1}{\left(x-2\right)\:\left(x-3\right)}$

$-3\left(-2a-3b+6c-8\right)$

$\frac{d^2y}{dx^2}=3x+1$