$\lim_{x\to\infty}\frac{x-7}{\left(x^2+1\right)^{\frac{1}{3}}}$
$\left(2^1\right)x\left(2^m\right)$
$a^2+32a+256$
$\int\frac{\left(2z+3\right)}{z^3+z^2-2z}dz$
$\frac{27a^3b^2}{3ab^2}$
$\left(2\right)^6-64$
$\int\frac{\left(x^2+3x\right)}{x-2}dx$
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