$\left(3a+2b\right)\left(3a+2c\right)$
$\left(x+4\right)\left(x-4\right)\left(1+x\right)$
$5x\left(x^2+7\right)$
$\int\frac{1}{\left(x+6\right)^2\left(x-4\right)}dx$
$\int\left(-6x.\:cos\:x\right)\:dx$
$\frac{x^3-2x^2+x+1}{x-1}$
$-199+-325$
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