$\frac{\ln\left(x\right)}{\ln\left(y\right)}=\frac{\ln\left(16y\right)-\ln\left(3\right)}{\ln\left(y\right)}-2$

$\left(3f^2-4g^3\right)^2$

$\int2\left(4x+5\right)^4dx$

$2\log\left(a^2b\right)=3+\log\left(a\right)-\log\left(b\right)$

$25-4y^2\:5-2y$

$2.5a^{2}-0.4a-3.6a^{2}+4a-1$

$49m^2-14m+1$