$\cos\left(x\right)=\frac{8}{13}$
$_{\left(sec^2-1\right)^2}$
$\int_1^5\left(\frac{x-1}{x^3+x}\right)dx$
$3x-6\ge7$
$\left(x^2+4\right)y'-3xy=x$
$\frac{-1}{2}ab+\frac{2}{3}c-\frac{1}{4}ab-\frac{3}{6}c-4c$
$tan=\frac{5}{4}$
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