$\lim_{x\to\frac{\pi}{3}}\left(\frac{2x}{\pi}\right)^{tan\left(x\right)}$

$\frac{\frac{1}{6}-\frac{8}{3x^2}}{\frac{2}{x}-\frac{1}{2}}$

$\lim_{x\to0}\left(\frac{x^3+\cos\left(x\right)-1}{5e^x+4x-5}\right)$

$12-\left(-7^0\right)+2^5$

$\frac{\left(2x^3z^2\right)^3}{x^3y^4z^2\cdot x^5}$

$-\left(x^2y^3\right)^6$

$12x-3\:>6x\:-2$