$5x^2-10x-2$
$\left(4a^3-3b^4\right)^3$
$-x^3+2x^2+3x\:=\:0$
$4x>10$
$x^2-13x+3$
$-36y+81$
$\left(\frac{3}{4}x-\frac{2}{3}y\right)^2$
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