$\lim_{x\to\infty}\left(\frac{2x+2}{6+3x}\right)^{2x+1}$
$\lim_{x\to\infty}-6x+20$
$f^2+5f+4$
$\int4xe^{2x+7}dx$
$-4x+3-x=23$
$\frac{\sin a}{\tan2a}=\cos a-\frac{\sin^2a}{\cos a}$
$x+5<9$
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