$$3x+4<13x+12$$

$$4x^3+3x^2=0$$

$$f\left(x\right)=in\left[2+in\left(x\right)\right]$$

$$\frac{3x^2+2x-1}{3x}$$

$$\int\frac{4x+1}{\left(x-1\right)\left(x+3\right)}dx$$

$$\int\frac{5x^4-2x^2-3x+2}{x-8}dx$$

$$\frac{32^2w^5+243^2y^5}{w+3y}$$