$7a-4b+5\:-7a+4a-6c$

$\left(x^2-6\right)+\left(3x+5\right)$

$\frac{\cos\:\left(2x\right)}{\sin\left(2x\right)+1}=\frac{\cos\left(x\right)-\sin\left(x\right)}{\cos\left(x\right)+\sin\left(x\right)}$

$\left(9.5\cdot10^{12}\right)\left(3.2\cdot10\right)$

$12ad-6a+10d-5$

$\left(\frac{3^3\cdot3^5}{3^{10}}\right)^{-3}$

$\int\frac{8x^2}{8x^3-3}dx$