$x-x^2-x^3$
$9x^2-6x=0$
$\frac{dy}{dx}=\frac{1}{4}\left(8-y\right)$
$x^2+26x+6^2$
$y'=\frac{x}{e^y}$
$\left(15\cdot3\cdot6\right):3$
$\frac{1+5}{2}$
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