$\sec\left(\theta\right)=-\frac{5}{4}$
$z^2-\frac{5}{2}z\:$
$20\cdot130$
$\frac{sec^4x+tan^4x}{sec^2xtan^2x}$
$3x+4y=-5$
$\left(\frac{2}{3}x^3-9y^2n\right)^2$
$\sin\left(x\right)\sec x^2\cos\left(y\right)^2dx+dy=0$
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