$9x^2+30x+25=0$
$\left(xy-1\right)\left(xy-3\right)$
$\frac{\sec\left(x\right)\cdot\tan\left(x\right)}{\sqrt{\left(1+sec\:x\right)}}$
$\frac{dy}{dx}\:y=\left(2x+3\right)^5\left(x-5\right)^3$
$x^2x\:x$
$0=18x^5$
$8x^2y+4xy$
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