$\infty^{-0.0000000000001}$
$x^4+12x^2\:+4$
$\left(\:m^3-\:y^4\right)^2$
$x^3-6x^2+8x$
$\frac{1}{6}\cdot\left(x^3+6\right)^2$
$-13\:-17\:-\left(-17\right)$
$3x\left(\sqrt{3x}\right)$
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