$\left(8^{-2}\right)^3$

$10^2\cdot10^9$

$\frac{1}{8}\cdot\:\left(3+4\cdot\:\:cos2x+cos4x\right)=cos^4x$

$\frac{4\sin\left(y\right)\left(\cos\left(y\right)\right)^3}{2\left(\cos\left(y\right)\right)^2}$

$\left(-3x+1\right)\left(3x^2-1\right)$

$\frac{1}{9}x^6y^4+\frac{2}{3}m^2x^3y^2+m^4$

$-[-2+7-\left(-7+\left(-7\right)+2\right)-1]$