$\lim_{x\to0}\left(1+4x\right)^{\frac{6}{x}}$

$\left(s\cdot4s^3\cdot s^2\right)^3$

$x^2+2x+1<0$

$\left(\sqrt[3]{4}-\sqrt[3]{x}\right)^3$

$x^{10}-y^8$

$\int\left(\left(x+2\right)^{-2}\right)dx$

$\cot\left(x\right)+\tan\left(x\right)=\tan\left(x\right)\cdot\sin^2x^{-2}$