x2+10x+20=0x^2+10x+20=0x2+10x+20=0
logx(93)=32\log_x\left(\frac{9}{\sqrt{3}}\right)=\frac{3}{2}logx(39)=23
10x−9x−11=24 \:10x-9x-11=24\:10x−9x−11=24
y′=yx+5xy'=\frac{y}{x}+5xy′=xy+5x
limt→∞(36⋅sin2(t)t2+100)\lim_{t\to\infty}\left(\frac{36\cdot\sin^2\left(t\right)}{t^2+100}\right)t→∞lim(t2+10036⋅sin2(t))
((−2)+((−4)x))2\left(\left(-2\right)+\left(\left(-4\right)x\right)\right)^2((−2)+((−4)x))2
c−0.51+0.3c-0.51+0.3c−0.51+0.3
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