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f(x)=12cos(x)+2412sin(x)-5/sin(x)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

12cos⁡(x)+24+12sin⁡(x)−5sin⁡(x)12\cos\left(x\right)+24+12\sin\left(x\right)-\frac{5}{\sin\left(x\right)}

Step-by-step Solution

1

Applying the cosecant identity: csc⁡(θ)=1sin⁡(θ)\displaystyle\csc\left(\theta\right)=\frac{1}{\sin\left(\theta\right)}

12cos⁡(x)+24+12sin⁡(x)−5csc⁡(x)12\cos\left(x\right)+24+12\sin\left(x\right)-5\csc\left(x\right)

Final answer to the exercise

12cos⁡(x)+24+12sin⁡(x)−5csc⁡(x)12\cos\left(x\right)+24+12\sin\left(x\right)-5\csc\left(x\right)

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12cos(x)+24+12sin(x)−5sin(x) 
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