$3\sqrt{6\cdot3+10}$
$cosx-cos\left(x\right)sin^2\left(x\right)=cos^3x$
$\frac{sin\left(x\right)}{\cos\left(x\right)-1}-\frac{sin\left(x\right)}{\cos\:\left(x\right)+1}$
$5^{\left(x+4\right)}=625$
$6\left(q+4\right)$
$\tan\left(x-30\right)=1\cdot$
$\left(3y-10\right)^2$
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