$36y^2-12y+1=0$

$\frac{\left(3x^2+14x+8\right)}{x-4}$

$6x^2+3x-2-x^2+7x+4$

$\:4cos\theta\:\:csc^2\theta\:\:tan^2\theta\:=4sec\theta\:$

$\frac{\sin\left(x\right)}{\sin\left(x\right)}-\sin^2\left(x\right)=\cos^2\left(x\right)$

$9x^2+12x=4$

$\frac{d}{dx}\left(8y-3x+5=0\right)$