$x^2y'+2xy=3x$
$5x+3+2x-y$
$\left(2x-1\right)\left(x-\frac{1}{5}\right)$
$17,456\cdot5,6$
$3-\left(\left(-7+4\right)\left(8-3\right)-5\right)$
$7 x + 3 \geq 5$
$\lim\:_{x\to\:0}\left(\left(4x^2-3\right)\cdot\:\left(7x^3+2x\right)\right)$
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