$\frac{\tan\left(x\right)-\sin\left(x\right)}{\sin\left(x\right)}$
$-20+15-34-15+10$
$\left(3x+y+1\right)^2$
$\frac{y}{y+xy}$
$3-2+5+3+3-7$
$\frac{dy}{dx}=y\left(x+2\right)$
$\frac{du}{dx}=\frac{3u-4}{2u-3}$
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