$-9x^2-24x-16>0$
$\frac{3a^2+13a+12}{2x+3}$
$10x^{2\:\:}-\:40x+40$
$\frac{z^9}{z^{16}}$
$10\cdot5+3$
$+2b\sqrt{10b^5+19b^4-4b^3+b^2}$
$\frac{\sqrt{5}}{1}$
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