$\frac{6x^2-3xy}{2xy^2-4x^2y}$
$\left(2x^a-8y^a\right)^2$
$\infty-17$
$5\left\{5-\left(-2\right)\right\}+8$
$sin^2x=2sinxcosx$
$\frac{x^2+9}{x+3}$
$4x^4-7x^3+6x^2+9x-12$
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