$\left(\frac{1}{3}m^2+\frac{3}{2}\right)^2$
$x^{10}+3x$
$2x-4+7x+3$
$\frac{\sec\left(a\right)}{1-\cos\left(a\right)}=\frac{\sec\left(a\right)+1}{\sin^2\left(a\right)}$
$\left(-2a^3b^4\right)-\left(-4a^3b^4\right)$
$\int_0^{400}\left(-0.0002x^3\right)dx$
$x+y+z=21$
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