$\left(x+z\right)\left(x^2-xz+z^2\right)$

$-0,3>u+7,8$

$\frac{x+5}{12}=\frac{2}{x}$

$\frac{d^5}{dx^5}\left(4x^2-e^x\right)$

$\frac{1+\cos\left(2y\right)}{\sin\left(2y\right)}=\frac{1}{\tan\left(y\right)}$

$\frac{d}{dx}\left(e^{\left(-2\cdot x\right)}\cdot cos\left(2\cdot x\right)^3\cdot sin\left(3\cdot x\right)^2\right)$

$c2-6c-27$