$125x^3+8y^3$
$7-\frac{1}{2}\left(x+4\right)=6$
$\int\sqrt[3]{u}du$
$\left(+35\right)\:x\:\left(+89\right)$
$20+90+51e$
$10-\left(-16\right)$
$\frac{d}{dx}x-y=xy^3+y^4$
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