$\left(3x^2y^3-5x^6y^7\right)^5$
$25-25x+25x^2$
$\frac{x^3+5x^2+6x+12}{x+4}$
$x+1\sqrt{x}$
$x''+x=0$
$\sqrt[5]{32m^2}n^{11}$
$\:3\left(x\:-\:4\right)\:=\:-3$
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