$10m^2n^4-16m^8$
$\lim_{x\to\infty}\left(\frac{2x^3+16}{x^2+4}\right)$
$2\cos\left(6x\right)\cdot\sin\left(3x\right)+\sin\left(3x\right)$
$\frac{dy}{dx}=\left(2x-1\right)^3$
$a-2^2-a+3^2$
$-\left(-3x^2+2x\right)^3$
$-\frac{1}{6}x=-5$
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