$\left(2x^2+6x\right)-\left(-3x^2+4x\right)$
$\int\frac{x}{x^2+4x+7}dx$
$\left(3x^5+4x\right)^2$
$\lim_{x\to3}\left(\frac{x-3}{x^{2}-3}\right)$
$2m^3n^2+6mn^3+8mn^2$
$5a-17^2+2a+4$
$-3x^2+6x+9<0$
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