$\left(-5\:+\:7\:\times\:1\right)\:-\:9\:\times\:5$
$4ab-7ab+8ab^2$
$\lim_{x\to1}_{\frac{\left(3x-5\right)}{x+1}}$
$8\cos\:x-4\sqrt{2}=0$
$36x^4-16$
$\frac{32}{x^2+3x+2}-3=\frac{x-3}{x+1}$
$\lim_{x\to-2}\left(\frac{c+2}{c^2-4}\right)$
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