$6x^2+2x+2=0$
$-3x\le-16$
$m^2+3m-4=0$
$\frac{d}{dx}y=\sqrt[7]{\frac{x-6}{x+4}}$
$\left(3x-7\right)\left(4x+7\right)$
$\int\sin^5\left(13x\right)dx$
$\left(\left(\left(x^6\right)^2\right)^3\right)^5$
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