15q(3q3)2\frac{15q}{\left(3q^3\right)^2}(3q3)215q
5x−3x+4y5x-3x+4y5x−3x+4y
(8+12i)2\left(8+12i\right)^2(8+12i)2
−63090-\frac{630}{90}−90630
−1x2−(−5y3)-\frac{1x}{2}-\left(-\frac{5y}{3}\right)−21x−(−35y)
tan(3a)=6\tan\left(3a\right)=6tan(3a)=6
x−52x−1≥1\frac{x-5}{2x-1}\ge12x−1x−5≥1
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