$\int\left(x\left(x+10\right)^9\right)dx$

$x^2+1-4x$

$\frac{dy}{dx}=\frac{\left(x^2+3x+2\right)}{\left(y-2\right)}$

$5.5r+3.5r$

$2\cos^2\left(x\right)-5=-9\cos^2\left(x\right)$

$\left(+5\right)-\left(-18\right)\left|\left(+9\right)-\left(+15\right)\right|$

$\left(\:-120\:\right)\:x\:\left(\:\:2\:\right)$