∫0πsec(x)4tan(x)dx\int_0^{\pi}\sec\left(x\right)^4\tan\left(x\right)dx∫0πsec(x)4tan(x)dx
limx→0(x216−x2−4)\lim_{x\to0}\left(\frac{x^2}{\sqrt{16-x^2}-4}\right)x→0lim(16−x2−4x2)
csc2(t)sec(t)=csc(t)tan(t)\frac{\csc^2\left(t\right)}{\sec\left(t\right)}=\csc\left(t\right)\tan\left(t\right)sec(t)csc2(t)=csc(t)tan(t)
48⋅3\sqrt{48}\cdot\sqrt{3}48⋅3
4m2−16n24m^2-16n^24m2−16n2
cot(a)+sec(a)⋅sin(a)=1cot\left(a\right)+sec\left(a\right)\cdot sin\left(a\right)=1cot(a)+sec(a)⋅sin(a)=1
limx→∞(ln(3x)x3)\lim_{x\to\infty}\left(\frac{\ln\left(3x\right)}{x^3}\right)x→∞lim(x3ln(3x))
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