$\left(4a+8\right)\left(4a+1\right)$

$y^2-ye^x=0$

$\lim_{x\to\infty}\left(\frac{\ln\left(x^2\right)}{\sqrt{x}}\right)$

$-\left(-32\::\:4\right).\left(-6\right).\left(-7\right)$

$\frac{3}{2x-4}<4$

$\lim_{x\to1}\left(\frac{u}{\left(x-1\right)}\cdot\left(1-u^{x-1}\right)\right)$

$\frac{6y^3}{18x}.2xy$