$m+0.47-0.4$
$\int\left(e^xtan^3\left(e^x\right)\right)dx$
$\int_{-\infty}^0e^x\cos\left(2x\right)dx$
$x^2+6x-4$
$6+\left(5+8\right)+4$
$\left(ab\right)\left(4ab+12ab^2\right)$
$\frac{1}{3}\left(9\:\left(3\right)^2\right)^{\frac{3}{2}}-\left(9-\left(0\right)^2\right)^{\frac{3}{2}}$
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