$x^2+\:x-12\:=\:0$
$3^3\sqrt{64b^3c^3}$
$2\infty\:-1$
$\frac{\left(x^{2}+1\right)^{3}}{\left(x^{2}-1\right)^{4}}$
$\frac{-4x}{2x}$
$\log_{64}x=\frac{1}{3}$
$\left(7cd+4c\right)+\left(5b\right)$
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