−9⋅(−12+4)-9\cdot\left(-12+4\right)−9⋅(−12+4)
∫1x2⋅ln(x)dx\int\frac{1}{x^2}\cdot ln\left(x\right)dx∫x21⋅ln(x)dx
(2u)3. 2u3u3\left(2u\right)^3.\:2u^3u^3(2u)3.2u3u3
(2x2−4x)(x2−2x−3)\left(2x^2-4x\right)\left(x^2-2x-3\right)(2x2−4x)(x2−2x−3)
5−[(−4)+2]5-\left[\left(-4\right)+2\right]5−[(−4)+2]
15a2b+20ab2−5a3b415a^2b+20ab^2-5a^3b^415a2b+20ab2−5a3b4
x3−0x2+0x+1x\frac{x^3-0x^2+0x+1}{x}xx3−0x2+0x+1
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