$f\left(x\right)\:=\:\left(2x^3+\:3x^2\right)\left(x^2+\:5x^3\:+5\right)$
$6x^2-3;\:x=2$
$\left(3x+2xy\right)^2$
$-370-1986$
$\left(-10\right):\left(-5\right)+2\cdot\left(3-8\right)$
$\frac{x^4-3x^2+2x+2}{x-1}$
$\frac{d}{dx}\left(\left(x-4\sqrt{x}\right)\right)$
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