$y'\:=\frac{2xy-4x+y-2}{\left(y-2\right)\cdot\:\left(x+2\right)}$
$\int\left(2x\left(x^2+3\right)^{13}\right)dx$
$x^2-8x+11\le0$
$6x+4\left(x-2\right)-11$
$\frac{9x^6}{25}+4y^2-\frac{12x^3y}{5}$
$\left(5+4x\right)-1\left(2x-8\right)$
$-2+2s<8$
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