$\int\frac{2tan^3\left(2\sqrt{x}\right)}{\sqrt{x}}dx$
$\left(1-\tan\theta\right)^{2}=\sec^{2}\theta-2\tan\theta$
$-18=-3+3u$
$3a^5-2a^4-8a^3$
$\frac{x}{x-2}=\frac{1}{2}+\frac{2}{x-2}$
$3n\:+\:8\:-\:5n\:+\:3$
$\frac{3x^3-2x^2+5}{-3+x^2}$
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