$\ln\left(t^2+3t\right)$
$\lim_{x\to\infty}\left(\frac{10\left(5+3x\right)}{1+0.004x}\right)$
$xy'+4y=8x^4$
$t^2+8t+16=0$
$f\left(x\right)=\frac{4}{3\sqrt[5]{x^3}}$
$\frac{\tan x}{1+\tan^{2}x}\equiv\cos x\sin x$
$\frac{b^2}{b}$
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